(x^2-2)-(x^2+x)=10-(3-x)

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Solution for (x^2-2)-(x^2+x)=10-(3-x) equation:


Simplifying
(x2 + -2) + -1(x2 + x) = 10 + -1(3 + -1x)

Reorder the terms:
(-2 + x2) + -1(x2 + x) = 10 + -1(3 + -1x)

Remove parenthesis around (-2 + x2)
-2 + x2 + -1(x2 + x) = 10 + -1(3 + -1x)

Reorder the terms:
-2 + x2 + -1(x + x2) = 10 + -1(3 + -1x)
-2 + x2 + (x * -1 + x2 * -1) = 10 + -1(3 + -1x)
-2 + x2 + (-1x + -1x2) = 10 + -1(3 + -1x)

Reorder the terms:
-2 + -1x + x2 + -1x2 = 10 + -1(3 + -1x)

Combine like terms: x2 + -1x2 = 0
-2 + -1x + 0 = 10 + -1(3 + -1x)
-2 + -1x = 10 + -1(3 + -1x)
-2 + -1x = 10 + (3 * -1 + -1x * -1)
-2 + -1x = 10 + (-3 + 1x)

Combine like terms: 10 + -3 = 7
-2 + -1x = 7 + 1x

Solving
-2 + -1x = 7 + 1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
-2 + -1x + -1x = 7 + 1x + -1x

Combine like terms: -1x + -1x = -2x
-2 + -2x = 7 + 1x + -1x

Combine like terms: 1x + -1x = 0
-2 + -2x = 7 + 0
-2 + -2x = 7

Add '2' to each side of the equation.
-2 + 2 + -2x = 7 + 2

Combine like terms: -2 + 2 = 0
0 + -2x = 7 + 2
-2x = 7 + 2

Combine like terms: 7 + 2 = 9
-2x = 9

Divide each side by '-2'.
x = -4.5

Simplifying
x = -4.5

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